Precalculus

Trigonometry

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Solving General Triangles

Solved Problems

Example 1.

Solve the triangle in which and

Solution.

This is an example of the case, so first we find the unknown angle

Now using the Sine Rule, we can calculate the sides and

Example 2.

Solve the triangle if and

Solution.

We know two sides and the angle between them, that is, we have the case. Therefore, we will use the Law of Cosines to solve the triangle.

Find the side

The angle can also be found by the Cosine Rule:

We see that so is a right triangle.

The remaining angle is equal to

Example 3.

Solve the triangle with sides

Solution.

We have here the case. Find the angle by the Cosine Rule:

Then

Similarly we calculate the angle

Hence,

The angle is given by

Example 4.

Solve the triangle in which and

Solution.

We are given an triangle, which includes two sides and the angle opposite one of these sides. This set of parameters is classified as an ambiguous case since it may have more than one solution. The unique solution exists if only the angle is opposite the longest side of the two given sides. In our case so the triangle is well defined.

Example of a SSA Triangle
Figure 6.

Using the Law of Sines, we find the angle

It follows from here that

Determine the third angle

The side can be found from the Law of Sines:

Example 5.

Given a parallelogram with sides and Find the length of the longer diagonal if the length of the shorter diagonal is

Solution.

A parallelogram given by the sides a, b and the shorter diagonal d1.
Figure 7.

Let the angle be equal to Write the Law of Cosines for triangle

and express in terms of

Similarly, given that , write the Cosine Rule for

By the reduction identity, Hence,

Substitute from the previous equation to obtain the length of the longer diagonal

Hence,

Example 6.

Derive Mollweide's formula where are the sides of an oblique triangle, and are the angles opposite to these sides, respectively.

Solution.

To prove the formula, we write the Sine Rule for the triangle:

It follows from this relationship that

Adding the two last equations gives us

Now we transform the expression in the numerator using the sum-to-product identity:

We also apply the double angle formula to in the denominator. As a result, we get

Since then using the cofunction identity, we have

that is,

Thus, we have proved Mollweide's formula

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