Differential Equations

Second Order Equations

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Nonlinear Pendulum

Solved Problems

Example 1.

Estimate the error in the calculation of the oscillation period of a simple pendulum at different amplitude α0 when using the standard formula T0=2πLg.

Solution.

We use the solution of the nonlinear equation of the pendulum, in which the expression for the period T is represented as a series. Taking into account the term n=1, the formula T(α0) looks like

T1(α0)=4LgK(k)=4LgK(sinα0)=4Lg[π2(1+14sin2α02)]=T0(1+14sin2α02),

where T0 is the period of oscillation, calculated by the standard formula

T0=2πLg.

Thus, the term 14sin2α02 immediately shows the deviation from the standard formula (expressed as a decimal), depending on the angle α0.

Similarly, we take into account the contribution of the following terms of the series for n=2 and n=3. The corresponding formulas have the form:

T2(α0)=T0(1+14sin2α02+964sin4α02),
T3(α0)=T0(1+14sin2α02+964sin4α02+2252304sin6α02).
Period of oscillations of a nonlinear pendulum in various approximations
Figure 3.

The graphs presented in Figure 3 show the value of the expression in the square brackets for the functions T1 and T2 (in percentage). In fact, they give the error in determining the period of oscillation when using the standard formula T0 compared with more accurate approximations.

It is seen that the power series converges well, and in the range of angles up to α0=20 it is possible to restrict the series expansion by the first term n=1 to ensure the accuracy rate of about 1%.

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