Calculus

Set Theory

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Inverse Functions

Suppose f : AB is a function whose domain is the set A and whose codomain is the set B. The function f is called invertible if there exists a function f −1 : BA with the domain B and the codomain A such that

f1(y)=x if and only if f(x)=y,

where x A, y B.

The function f −1 is then called the inverse of f.

Not all functions have an inverse. If a function f is not injective, different elements in its domain may have the same image:

f(x1)=f(x2)=y1.
Not injective function does not have an inverse.
Figure 1.

In this case, the converse relation f1 is not a function because there are two preimages x1 and x2 for the element y1 in the codomain B. So, to have an inverse, the function must be injective.

If a function f is not surjective, not all elements in the codomain have a preimage in the domain. In this case, the converse relation f1 is also not a function.

Not injective function does not have an inverse.
Figure 2.

Thus, to have an inverse, the function must be surjective.

Recall that a function which is both injective and surjective is called bijective. Hence, to have an inverse, a function f must be bijective. The converse is also true. If f:AB is bijective, then it has an inverse function f1.

Any bijective function has an inverse function.
Figure 3.

See solved problems on Page 2.

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