Calculus

Applications of Integrals

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Area of a Region Bounded by Curves

Solved Problems

Example 5.

Find the area of the region enclosed by the curve and the line

Solution.

It is easy to see that the curve and the straight line intersect at the points (Figure ).

Area of the region enclosed by the functions y=sqrt(x+1) and y=x+1.
Figure 10.

Then

Example 6.

Find the area of the region enclosed by the root curve and the line where

Solution.

First we find the points of intersection of both curves:

Area of the region enclosed by the root curve y=sqrt(x) and the line y=kx.
Figure 11.

Now we calculate the area using integration:

Example 7.

Find the area of the region bounded by the curve and the lines

Solution.

Area of the region bounded by the curve y=2^x and the lines x=0, y=2.
Figure 12.

The upper graph is and the lower curve is Hence, the area is

Example 8.

Find the area enclosed by the three petaled rose

Solution.

Area of a region bounded by the three petal rose r=sin(3*theta)
Figure 13.

Since each petal has the same area, we calculate the area of one petal and multiply the result by three. So we have

Hence, the area of the all region is

Example 9.

Find the area enclosed by the cardioid

Solution.

Area enclosed by the cardioid r=1+cos(theta).
Figure 14.

We can easily the area of the cardioid by integrating the polar equation in the interval This yields:

Example 10.

Find the area of the region bounded by the astroid

Solution.

We represent the equation of the astroid in parametric form:

Check by substitution:

which is true.

Let's now calculate the area of the region enclosed by the parametric curve.

Area of the region enclosed by astroid x^(3/2)+y^(3/2)=1.
Figure 15.

We apply the following integration formula:

As

we have

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